SOLUTION: find the equation of a line containing the points (-2,-4),(-8,-7).
I have tried to but i am not understanding. I do really good until I get to the end. I keep following the exampl
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-> SOLUTION: find the equation of a line containing the points (-2,-4),(-8,-7).
I have tried to but i am not understanding. I do really good until I get to the end. I keep following the exampl
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Question 317620: find the equation of a line containing the points (-2,-4),(-8,-7).
I have tried to but i am not understanding. I do really good until I get to the end. I keep following the examples in my lesson but I don't understand how they are getting the answers they are getting Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! (-2,-4),(-8,-7).
Y=mX+b is the line equation.
m=the slope=(Y2-Y1)/(X2-X1)
b=the Y intercept.
m=(-7+4)/(-8+2)=-3/-6=1/2 ans. for the slope.
-4=1/2*-2+b
-4=-1+b
b=-4+1
-3 ans. for the Y intercept.
y=x/2-3 is this line equation.
Proof: (graph 300x200 pixels, x from -10 to 5, y from -10 to 10, x/2 -3).
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