SOLUTION: One of the accepted functions used to express this correspondence is: h(x) = 1.95 x + 72.85. where (the domain) x= length of the femur bone in cm and (the range ) h is the heigh

Algebra ->  Functions -> SOLUTION: One of the accepted functions used to express this correspondence is: h(x) = 1.95 x + 72.85. where (the domain) x= length of the femur bone in cm and (the range ) h is the heigh      Log On


   

Question 276518: One of the accepted functions used to express this correspondence is: h(x) = 1.95 x + 72.85.
where (the domain) x= length of the femur bone in cm and (the range ) h is the height of the female subject in cm. (Brand, 2009).
Show all detail calculations and find answers to 2 decimal precision.
a) Find the height of a female whose femur is 35 cm long


b) Find the length of a femur in a female who is 165 cm tall.


c) What is an invalid value for the domain in this function. Using the function, show why it is invalid using lucid and correct algebraic detail calculations.

Answer by wayne2343(1) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+2%2C%0D%0A++++1%5Cx+%2B+-1%5Cy+=+0+%29%0D%0A++

Any system of equations:


has solution

or



(x=1, y=1}
Solved by pluggable solver: SUBSTITUTION solver -- compute expression given values
Your Result:


YOUR ANSWER


  • Graphical form: x%5E2-2x simplifies to 3
  • Text form: x^2-2x simplifies to 3
  • Cartoon (animation) form: simplify_cartoon%28+x%5E2-2x+%29
    For tutors: simplify_cartoon( x^2-2x )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at highlight_red%28+x+%29%5E2-2%2Ax.
Replaced x with 3
It becomes highlight_green%28+3+%29%5E2-2%2Ax.
Look at highlight_red%28+3+%29%5Ehighlight_red%28+2+%29-2%2Ax.
Replace constants in factor: highlight_red%28+3+%29,highlight_red%28+2+%29 with highlight_green%28+9+%29
It becomes highlight_green%28+9+%29-2%2Ax.
Look at 9-2%2Ahighlight_red%28+x+%29.
Replaced x with 3
It becomes 9-2%2Ahighlight_green%28+3+%29.
Look at highlight_red%28+9+%29-highlight_red%28+2%2A3+%29.
Replace constants in expression: highlight_red%28+9+%29,highlight_red%28+-2%2A3+%29 with highlight_green%28+3+%29
It becomes highlight_green%28+3+%29.
Result: 3

Universal Simplifier and Solver


Done!