SOLUTION: sketch the graph of f(x)=(x-3)(x+2)(x+5) using the zeros and end behaviours.

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Question 218712: sketch the graph of f(x)=(x-3)(x+2)(x+5) using the zeros and end behaviours.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The zeros are at x=3, x=-2, and x=-5. The graph is actually of the form y=x^3, so it opens "up" on the right side and "down" on the left side of the graph. At each x intercept, the graph passes "through" the zero.

graph%28300%2C300%2C-7%2C7%2C-30%2C30%2C+%28x-3%29%28x%2B2%29%28x%2B5%29+%29

For additional explanation on this topic, please go to my website. Do a "Bing" search for my last name "Rapalje". Look for "Rapalje Homepage" at the top of this search. Look near the top of my Homepage for "MATH IN LIVING COLOR", click on "College Algebra" and look for Section 3.03 Polynomial Functions. The lesson is keyed to the TI 83/84 Graphing Calculator.

R^2

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus