Question 217482: find the distance between P(-8,4) and Q(3,-2).
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! P(-8,4),,,,,Q(3,-2)
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Remember the distance formula,,,d= sqrt{(y2-y1)^2 + (x2-x1)^2}
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d=sqrt{ (4-(-2))^2 + (-8-3)^2}
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d = sqrt{ 6^2 + (-11)^2)
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d= sqrt{ 36+121}
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d=sqrt { 157}
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d= 12.53
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checking,,,a rough sketch shows the legs of a rt triangle to be 11 and 6,,,,,and the hypotenuse = sqrt( 121+36) =12.53,,,,,ok
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