SOLUTION: What is the domain of y = rqst(4x + 1)

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Question 213443This question is from textbook College Algebra in Context
: What is the domain of y = rqst(4x + 1) This question is from textbook College Algebra in Context

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
To find the domain of a function, make sure DENOMINATORS are NOT ZERO, and RADICANDS (whatever is inside the square root!) must be GREATER THAN OR EQUAL TO ZERO!!

In this case 4x%2B1%3E=0,
so 4x%3E=-1
x%3E=-1%2F4

If you need additional help with Domain and Range, check out my website by doing a "Bing" search for my last name "Rapalje". Look for "Rapalje Homepage" at the top of the search list, and choose the link on my homepage "Math in Living Color." Click on "College Algebra", and look for "Section 2.07, Functions, Domain, and Range." My non-traditional explanation should be easier to understand than your textbook!

R^2

Dr. Robert J. Rapalje, Retired
Seminole Community College
Altamonte Springs Campus
Florida