SOLUTION: how do i find the domain of f(x)= 1/x^2+9?
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Question 186245
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how do i find the domain of f(x)= 1/x^2+9?
Answer by
nerdybill(7384)
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Domain specifies the possible values of 'x' for your equation:
f(x)= 1/x^2 + 9
The only values that will make the equation undefined is when the denominator of 1/x^2 equals zero:
This is true only when x does NOT equal 0
Therefore the range is "all real numbers except 0"