SOLUTION: train A and train B are traveling in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 96 miles per hour train A passes a

Algebra ->  Functions -> SOLUTION: train A and train B are traveling in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 96 miles per hour train A passes a      Log On


   

Question 177621: train A and train B are traveling in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 96 miles per hour train A passes a station at 10:20pm if train B passes the same station at 10:35pm what time will train B catch up to train A?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Train A and train B are traveling in the same direction on parallel tracks.
train A is traveling at 80 miles per hour and train B is traveling at 96 miles
per hour train A passes a station at 10:20pm if train B passes the same station
at 10:35pm what time will train B catch up to train A?
:
from the given information, we know that train B is 15 min (1/4 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: 1%2F4 * 96 = 24 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train A travel dist = Train b travel dist + 24 mi
96t = 80t + 24
96t - 80t = 24
16t = 24
t = 24%2F16
t = 1.5 hr or 1 hr 30 min
:
10:20 + 1:30 = 11:50 pm, B catches A