Question 177116: Could someone check my work to see if I am looking at this from the right perspective.
Consider two identical six sided dice with from one to six dots on each side with no two sides containing the same number of dots.
a. Question: How many possible outcomes (sum of dots) are there if you throw the two dice on the board?
Answer: 12
b. Question: If you throw both dice on a table what are the chances that the sum of the dots on the two dice will be equal to 6?
Answer: 1/36
c. same as in (b) but for the sum of 7?
Answer: {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} 6/36=1/6
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Consider two identical six sided dice with from one to six dots on each side with no two sides containing the same number of dots.
a. Question: How many possible outcomes (sum of dots) are there if you throw the two dice on the board?
Answer: 12
I think it is 11. Sums range from 2 to 12
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b. Question: If you throw both dice on a table what are the chances that the sum of the dots on the two dice will be equal to 6?
Answer: 1/36
Think of (1,5)(2,4)(3,3)(4,2)(5,1)
Ans: 5/36
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c. same as in (b) but for the sum of 7?
Answer: {(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)} 6/36=1/6
Correct
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Cheers,
Stan H.
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