SOLUTION: This is another form of problem that I am having trouble with. I would appreciate any help you can give me. d varies inversely as w and directly as the square of v. If d=40 wh

Algebra ->  Functions -> SOLUTION: This is another form of problem that I am having trouble with. I would appreciate any help you can give me. d varies inversely as w and directly as the square of v. If d=40 wh      Log On


   



Question 167607: This is another form of problem that I am having trouble with. I would appreciate any help you can give me.
d varies inversely as w and directly as the square of v. If d=40 when w=6 and v=2, find d when w=9 and v=4.
d=kv2
40=k(4)2
40=k(16)
40/16=k
5/2=k

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
d varies inversely as w and directly as the square of v.
This translates to:
d =%28kv%5E2%29%2Fw
:
If d=40 when w=6 and v=2,
40 = %28k%2A2%5E2%29%2F6
Find k
%284k%29%2F6 = 40
:
Multiply both sides by 6
4k = 6*40
4k = 240
k = 240%2F4
k = 60
;
The equation: d = %2860v%5E2%29%2Fw


find d when w=9 and v=4.
d = %2860%284%5E2%29%29%2F9
d = %2860%2816%29%29%2F9
d = 960%2F9
d = 1062%2F3