Question 163001: Please help.
Given the following information, find the range.
f(x)=2(x-3)^2 + 2
vertex is (3,2)
What is the range?
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! For a quadratic equation of this kind (a parabola), the range is determined by the maximum or minimum and comes in the form of
( , )
or
( , )
.
.
.
The min or max occurs at the vertex.
The only thing left to determine is whether f(3)=2 is a min or max value.
That's determined by the coefficient (a) of the  term,
if a>0, parabola opens up, min value.
if a<0, parabola opens down, max value.
In this case, a=2, min. value.
.
.
.
The range of the parabola is then,
( ,)
|
|
|
