SOLUTION: I need an explanation on how to solve this problem: Determine the domain of the function f(x){{{ sqrt( x^2+8x ) }}} Thank you

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Question 162851This question is from textbook Precalculus with Limits a Graphing Approach Third Edition
: I need an explanation on how to solve this problem:
Determine the domain of the function
f(x)+sqrt%28+x%5E2%2B8x+%29+
Thank you
This question is from textbook Precalculus with Limits a Graphing Approach Third Edition

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the domain:
Recall that the domain of a function is the set of all of the values of the independent for which the function is defined, in other words, all of the x-coordinate values.
f%28x%29+=+sqrt%28x%5E2%2B8x%29 Notice that, for some values of x, the radicand becomes negative and, at these points, the function is not defined, thus these values of x would be excluded values.
What values of x would make %28x%5E2%2B8x%29+%3C+0
The answer might be easier to see if you were to factor the radicand:
%28x%28x%2B8%29%29+%3C+0
If x = -7, you would have:
%28-7%28-7%2B8%29%29+=+-7 So x = -7 is a candidate for eclusion.
if x = -6, you would have:
%28-6%28-6%2B8%29%29+=+-12 So x = -6 is a candidate for exclusion.
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.
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If x = -1, you would have:
%28-1%28-1%2B8%29%29+=+-7 So x = -1 is a candidate for exclusion.
For all other values of x, the function is defined.
So the domain would be:
-7+%3E+x+%3E=+0