SOLUTION: Find g(a+1) when g(x)= 1/4x - 3.

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Question 135413: Find g(a+1) when g(x)= 1/4x - 3.
Answer by nycsharkman(136) About Me  (Show Source):
You can put this solution on YOUR website!
Find g(a+1) when g(x)= 1/4x - 3.
Do you see x in the function g(x)?
Replace every x with (a + 1) and simplify.
g(a + 1) = 1/4(a + 1) - 3
g(a + 1) = 1/4a + 4 - 3
g(a + 1) = 1/4a + 1
Did you follow? I just found the value of g(a + 1) and it is the fraction
1/4a + 1