SOLUTION: Ok, this question is so confusing, the problem is: If y varies as x^2, and y=2 when x=4, what is the constant of variation? Please and Thank you=)

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Question 130547This question is from textbook algebra
: Ok, this question is so confusing, the problem is: If y varies as x^2, and y=2 when x=4, what is the constant of variation?
Please and Thank you=) This question is from textbook algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
"y varies as x^2" can be written as:
y+=+kx%5E2 where k is the constant of variation.
To find the value of k, simply substitute the given values of y = 2, and x = 4 and solve for k.
2+=+k%284%29%5E2
2+=+16k Divide both sides by 16.
2%2F16+=+k Simplify.
k+=+1%2F8