SOLUTION: Determine the solution to the double inequality 28≤2(4x+9)<5(x+7)≤64

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Question 1204560: Determine the solution to the double inequality 28≤2(4x+9)<5(x+7)≤64
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

28%3C=++2%284x%2B9%29%3C5%28x%2B7%29+%3C=+64
first do
28%3C=++2%284x%2B9%29
28%3C=8x%2B18
28-18%3C=8x
10%3C=8x
10%2F8%3C=x
5%2F4%3C=x

then do
2%284x%2B9%29%3C5%28x%2B7%29
8x%2B18%3C5x%2B35
8x-5x%3C-18%2B35
3x%3C17
x%3C17%2F3

so we have
+5%2F4%3C=x%3C17%2F3+
since all will be <= 64
solution is:
5%2F4%3C=x%3C17%2F3+