SOLUTION: GIVEN THE FUNCTIONS F(X)= 3X^2-5X+4, G(X)=3X/X-2, H(X)=THE SQUARE ROOT OF 2-X FIND:
F(X-1), G(X+H), AND H(X+2). COULD YOU SHOW ME STEP BY STEP HOW YOU WOULD SOLVE THESE PROBL
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-> SOLUTION: GIVEN THE FUNCTIONS F(X)= 3X^2-5X+4, G(X)=3X/X-2, H(X)=THE SQUARE ROOT OF 2-X FIND:
F(X-1), G(X+H), AND H(X+2). COULD YOU SHOW ME STEP BY STEP HOW YOU WOULD SOLVE THESE PROBL
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Question 118535: GIVEN THE FUNCTIONS F(X)= 3X^2-5X+4, G(X)=3X/X-2, H(X)=THE SQUARE ROOT OF 2-X FIND:
F(X-1), G(X+H), AND H(X+2). COULD YOU SHOW ME STEP BY STEP HOW YOU WOULD SOLVE THESE PROBLEMS? THANK YOU VERY MUCH
You can put this solution on YOUR website! GIVEN THE FUNCTIONS
F(X)= 3X^2-5X+4
F(X-1) = 3(X-1)^2-5(X-1)+4
= 3(x^2-2x+1)-5x-5+4
= 3x^2-6x+3-5x-1
= 3x^2-11x+2
-----------------------
G(X)=3X/X-2
G(x+h) = 3(x+h)/x+h-2
= [3x+3h]/[x+h-2]
----------------------
H(X)=THE SQUARE ROOT OF 2-X
H(X+2) = sqrt(2-(x+2))
= sqrt(-x)
==================
Cheers,
Stan H.
You can put this solution on YOUR website! (Please do not type your questions in ALL CAPS. It is hard to read, annoying, and is the electronic equivalent of SHOUTING.)
A:
In the expression for , substitute every place you see , thus:
Then expand and simplify by collecting terms:
B:
What is ? , so .
Again, take the definition of and substitute every place you see .
(I'm not sure I even want to begin to try to simplify that horror. I'd just leave it be and hope for the best)
There is also the possibility that I misinterpreted your expression for . In the event that you actually meant , this problem comes out quite differently.
, then
Rationalizing the denominator:
C:
Do this one exactly the same way I did the first one. Take and substitute everywhere you see . I'll let you finish.
Super-Double-Plus Extra Credit: What is the domain of ?
(