SOLUTION: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?

Algebra ->  Functions -> SOLUTION: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?      Log On


   

Question 1169878: let f(x)=-2x^3+3x^2+36x over the closed interval (-3,5) what is the smallest critical point?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
f'(x)=-6x^2+6x+36
set that equal to 0
6x^2-6x-36=0, multiplying by -1
x^2-x-6=0 dividing by 6 both sides
(x-3)(x+2)=0
x=-2, 3
-2
graph%28300%2C300%2C-3%2C5%2C-100%2C100%2C-2x%5E3%2B3x%5E2%2B36x%29