SOLUTION: I would truly appreciate help with the following:
I am given the following coordinates (-5,-4),(-1,-4),(0,-4),(3,-4),(4,-4)
a. What is the x-intercept(s)? Type an integer usi
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-> SOLUTION: I would truly appreciate help with the following:
I am given the following coordinates (-5,-4),(-1,-4),(0,-4),(3,-4),(4,-4)
a. What is the x-intercept(s)? Type an integer usi
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Question 1122137: I would truly appreciate help with the following:
I am given the following coordinates (-5,-4),(-1,-4),(0,-4),(3,-4),(4,-4)
a. What is the x-intercept(s)? Type an integer using commas to separate answers.
b. What is the y-intercept(s)? Type an integer using commas to separate answers.
c. What is the missing function value indicated by the question mark
f(-5)+ f(3)=? Answer by solver91311(24713) (Show Source):
There is no -intercept. I must assume without any other information, that the given points are all of the elements of the set that comprise your function. In other words:
The -intercept of any function is the ordered pair(s) that is an element of the set that enumerates the function where the -coordinate is equal to zero.
The -intercept is the point where the -coordinate is zero.
The value of the function at any point in its domain is -4. So the indicated sum is two instances of the function evaluated at two different values from the domain of the function, each of which evaluates to -4, added together. I'll let you ponder the actual arithmetic involved. Here is a point of view that may eliminate some of the confusion, at least as far as this part of the question is concerned: Stop thinking about ordered pairs as , rather think of them as
John
My calculator said it, I believe it, that settles it
