multiply both sides of the equation by 4 to get 4y = 2x + 3
subtract 3 from both sides of the equation to get 4y-3 = 2x
divide both sides of the equation by 2 to get (4y-3)/2 = x
now replace x with y and y with x to get (4x-3)/2 = y
switch sides to get y = (4x-3)/2.
replace y with f^-1(x) to get f^-1(x) = (4x-3)/2
that's your inverse equation.
to graph replace f(x) with y and replace f^-1(x) with y and graph both equations.
you will graph y = (2x+3)/4 and y = (4x-3)/2
your graph looks like this:
red is your normal equation.
blue is your inverse equation.
you can tell these are inverse equations of each other because they are refledtions about the line y = x and f(a,b) = f^-1(b,a).
that's evident when you look at the intersection of both lines with the line y = -x + 8, where a is equal to 4.137 and b is equal to 4.833.