SOLUTION: f(x)= x^2-3x-10 --------- x^-6x+9 --- means divided by find the domain and find the x-intercepts

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Question 110923: f(x)=
x^2-3x-10
---------
x^-6x+9

--- means divided by
find the domain
and
find the x-intercepts

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28x%5E2-3x-10%29%2F%28x%5E2-6x%2B9%29 Start with the given function


x%5E2-6x%2B9=0 Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.




%28x-3%29%28x-3%29=0 Factor the left side (note: if you need help with factoring, check out this solver)




Now set each factor equal to zero:

x-3=0 or x-3=0

x=3 or x=3 Now solve for x in each case


Since these two answers are the same, our only solution is x=3



Since x=3 makes the denominator equal to zero, this means we must exclude x=3 from our domain

So our domain is:

which in plain English reads: x is the set of all real numbers except x%3C%3E3

So our domain looks like this in interval notation


note: remember, the parenthesis excludes 3 from the domain



To find the x-intercepts, set the entire expression equal to zero

0=%28x%5E2-3x-10%29%2F%28x%5E2-6x%2B9%29


So this means the numerator can only equal zero

x%5E2-3x-10=0



%28x-5%29%28x%2B2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:

x-5=0 or x%2B2=0

x=5 or x=-2 Now solve for x in each case


So our solutions are x=5 or x=-2

This means the x intercepts are (-2,0) or (5,0)


Notice if we graph f%28x%29=%28x%5E2-3x-10%29%2F%28x%5E2-6x%2B9%29, we can see that the x intercepts are (-2,0) or (5,0) and x=3 is not in the domain


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%5E2-3x-10%29%2F%28x%5E2-6x%2B9%29%29+


So this verifies our answer.