SOLUTION: For the equation f(x)=(-1/2)(x+3)^2+6 determine:
The vertex of the graph of f(x) & the axis of symmetry of the graph f(x)
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-> SOLUTION: For the equation f(x)=(-1/2)(x+3)^2+6 determine:
The vertex of the graph of f(x) & the axis of symmetry of the graph f(x)
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Question 1100535: For the equation f(x)=(-1/2)(x+3)^2+6 determine:
The vertex of the graph of f(x) & the axis of symmetry of the graph f(x) Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Vertex is minus the -3 and plus the 6 or (3, 6)
axis of symmetry is around x=3
check by (-1/2)(x^2+6x+9)+6
This is (-1/2)x^2-3x-4.5+6
or -(1/2)x^2-3x+1.5
vertex x-value and axis of symmetry is at -b/2a=3/-1=-3
