SOLUTION: The sum of the digits of a 3-digit number is 20. If the tens were the hundreds digit and the hundreds digit were the tens digit, the resulting number would be 90 less than the orig

Algebra ->  Functions -> SOLUTION: The sum of the digits of a 3-digit number is 20. If the tens were the hundreds digit and the hundreds digit were the tens digit, the resulting number would be 90 less than the orig      Log On


   

Question 1097280: The sum of the digits of a 3-digit number is 20. If the tens were the hundreds digit and the hundreds digit were the tens digit, the resulting number would be 90 less than the original number. If the tens were the units digit and the units digit were the tens digit, the resulting number would be 45 less than the original number. What is the number?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
h, t, u



-
system%28h%2Bt%2Bu=20%2C-90h%2B90t=-90%2C-9t%2B9u=-45%29
system%28-h%2Bt=-1%2C-t%2Bu=-5%2Ch%2Bt%2Bu=20%29

-
h-t=1
h=t%2B1
-
u=t-5

Substituting for h and u in the digit sum,
%28t%2B1%29%2Bt%2B%28t-5%29=20
3t-4=20
3t=24
highlight%28t=8%29--------finding the other two digits (h and u) should be simple.

Original Number:
983