SOLUTION: Need help with my son's Algebra: Find the x-intercepts for the function f(x)=(x+2)^2-16 Thank you

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Question 1086692: Need help with my son's Algebra:
Find the x-intercepts for the function f(x)=(x+2)^2-16
Thank you
Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.
x- intercepts are intersection points of the parabola f(x) with the x-axis, where 

   f(x) = 0,  or,  which is the same,  %28x%2B2%29%5E2-16 = 0.


So, you need to solve the equation  %28x%2B2%29%5E2-16 = 0.

It is equivalent to  %28x%2B2%29%5E2 = 16.


Take the square root from both sides.  You will get

x + 2 = +/- 4.


So, there are two options and two solutions. They are


1)  x + 2 = 4   ====>  x = 4 - 2 = 2.


2)  x + 2 = -4  ====>  x = -4 - 2 = -6.


Answer.  There are two solutions: x= 2  and  x= -6.

Solved.