SOLUTION: For a x in the domain of the function (x+2)/(x^3-x), this function is equivalent to:
F) (1/x^2-1)+(2/x^3-x) G) (2/x^2-1) H) (1/x^2-1) J) (1/x-1) K) (1/x+1)
I got G by doi
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-> SOLUTION: For a x in the domain of the function (x+2)/(x^3-x), this function is equivalent to:
F) (1/x^2-1)+(2/x^3-x) G) (2/x^2-1) H) (1/x^2-1) J) (1/x-1) K) (1/x+1)
I got G by doi
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Question 1084549: For a x in the domain of the function (x+2)/(x^3-x), this function is equivalent to:
F) (1/x^2-1)+(2/x^3-x) G) (2/x^2-1) H) (1/x^2-1) J) (1/x-1) K) (1/x+1)
I got G by doing (x+2)/x(x^2-1) and cancelling out the x's, but the actual answer is F. How do I get F? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Break out the numerator so that
(x+2)/(x^3-x)=x/(x^3-x) + 2/(x^3-x)
The first term of that will become 1/(x^2-1)
