SOLUTION: Suppose $P(x)$ is a polynomial of smallest possible degree such that:
$\bullet$ $P(x)$ has rational coefficients
$\bullet$ $P(-3) = P(\sqrt 7) = P(1-\sqrt 6) = 0$
$\bullet
Algebra ->
Functions
-> SOLUTION: Suppose $P(x)$ is a polynomial of smallest possible degree such that:
$\bullet$ $P(x)$ has rational coefficients
$\bullet$ $P(-3) = P(\sqrt 7) = P(1-\sqrt 6) = 0$
$\bullet
Log On
Question 1075770: Suppose $P(x)$ is a polynomial of smallest possible degree such that:
$\bullet$ $P(x)$ has rational coefficients
$\bullet$ $P(-3) = P(\sqrt 7) = P(1-\sqrt 6) = 0$
$\bullet$ $P(-1) = 8$
Determine the value of $P(0)$. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Rational coefficients and irrational roots means the irrational roots occur as conjugate pairs.
So,
So then,
.
.
.
