SOLUTION: find an equation of the circle whose diameter has endpoints (3, -5) and (3, 1).

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Question 1059828: find an equation of the circle whose diameter has endpoints (3, -5) and (3, 1).
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Center at system%28x=%283%2B3%29%2F2=3%2F2%2Cy=%28-5%2B1%29%2F2=-2%29; and the radius, figurable from the two endpoints of the diameter, is 3 units in size.

%28x-3%2F2%29%5E2%2B%28y%2B2%29%5E2=9

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
find an equation of the circle whose diameter has endpoints (3, -5) and (3, 1). 
Center of circle: (3, - 2)

%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2 ------ Center-radius form of equation of circle

%283+-+3%29%5E2+%2B+%281+-+-+2%29%5E2+=+r%5E2 -------- Substituting point (3, 1) for (x, y) and center (3, - 2) for (h, k)

9+=+r%5E2 ======> r 

Equation of circle: highlight_green%28%28x+-+3%29%5E2+%2B+%28y+%2B+2%29%5E2+=+9%29

Anyone who says otherwise is WRONG!