SOLUTION: if X^4+aX^3-3X^2+2aX+a^2 is aperfect square and has a factor (X+2). find (a), when (a) has this vàlue to obtain the square root of the expression in its factorized form

Algebra ->  Functions -> SOLUTION: if X^4+aX^3-3X^2+2aX+a^2 is aperfect square and has a factor (X+2). find (a), when (a) has this vàlue to obtain the square root of the expression in its factorized form      Log On


   



Question 1048380: if X^4+aX^3-3X^2+2aX+a^2 is aperfect square and has a factor (X+2). find (a), when (a) has this vàlue to obtain the square root of the expression in its factorized form
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
This must be an identity

x%5E4%2Bax%5E3-3x%5E2%2B2ax%2Ba%5E2%22%22=%22%22%28%28x%2B2%29%28x%2Bk%29%5E%22%22%29%5E2

If x=0

%280%29%5E4%2Ba%280%29%5E3-3%280%29%5E2%2B2a%280%29%2Ba%5E2%22%22=%22%22%28%28%280%29%5E%22%22%2B2%29%28%280%29%5E%22%22%2Bk%29%5E%22%22%29%5E2

a%5E2%22%22=%22%22%282k%29%5E2

a%22%22=%22%22%22%22+%2B-+2k

If x=1

%281%29%5E4%2Ba%281%29%5E3-3%281%29%5E2%2B2a%281%29%2Ba%5E2%22%22=%22%22%28%28%281%29%5E%22%22%2B2%29%28%281%29%5E%22%22%2Bk%29%5E%22%22%29%5E2

1%2Ba-3%2B2a%2Ba%5E2%22%22=%22%22%28%281%2B2%29%281%2Bk%29%5E%22%22%29%5E2

1%2Ba-3%2B2a%2Ba%5E2%22%22=%22%22%283%281%2Bk%29%5E%22%22%29%5E2

1%2Ba-3%2B2a%2Ba%5E2%22%22=%22%229%281%2Bk%29%5E2

Substituting a%22%22=%22%222k

1%2B%282k%29-3%2B2%282k%29%2B%282k%29%5E2%22%22=%22%229%281%2Bk%29%5E2

4k%5E2%2B6k-2%22%22=%22%229k%5E2%2B18k%2B9

-5k%5E2-12k-11%22%22=%22%220

5k%5E2%2B12k%2B11%22%22=%22%220

Discriminant = 12%5E2-4%2A5%2A11=144-220=-76

So it has imaginary solutions.  We ignore a%22%22=%22%222k


Substituting a%22%22=%22%22-2k

1%2B%28-2k%29-3%2B2%28-2k%29%2B%28-2k%29%5E2%22%22=%22%229%281%2Bk%29%5E2

1-2k-3-4k%2B4k%5E2%22%22=%22%229%281%2B2k%2Bk%5E2%29

4k%5E2-6k-2%22%22=%22%229k%5E2%2B18k%2B9

-5k%5E2-24k-11%22%22=%22%220

5k%5E2%2B24k%2B11%22%22=%22%220

Discriminant = 24%5E2-4%2A5%2A11=576-220=356

That has real solutions

5k%5E2%2B24k%2B11%22%22=%22%220

k%22%22=%22%22%28-24+%2B-+sqrt%2824%5E2-4%2A5%2A11+%29%29%2F%282%2A5%29+

k%22%22=%22%22%28-24+%2B-+sqrt%28356+%29%29%2F10+

k%22%22=%22%22%28-24+%2B-+sqrt%284%2A89%29%29%2F10+

k%22%22=%22%22%28-24+%2B-+2sqrt%2889%29%29%2F10+

k%22%22=%22%22%282%28-12+%2B-+sqrt%2889%29%29%29%2F10+

k%22%22=%22%22%28-12+%2B-+sqrt%2889%29%29%2F5+ 

a%22%22=%22%22-2k

k%22%22=%22%22%28-12+%2B-+sqrt%2889%29%29%2F5+

a%22%22=%22%22-2%2Aexpr%28%28-12+%2B-+sqrt%2889%29%29%2F5%29+

a%22%22=%22%22%2824+%2B-+2sqrt%2889%29%29%2F5+

So

%28%28x%2B2%29%28x%2Bk%29%5E%22%22%29%5E2

%28%28x%2B2%29%28x%2B%28%28-12+%2B-+sqrt%2889%29%29%2F5%29%29%5E%22%22%29%5E2

expr%281%2F25%29%28%28x%2B2%29%5E%22%22%285x-sqrt%2889%29-12%29%29%5E2

Edwin