SOLUTION: What makes this statement false?
if {{{ f(x) = x + 1 }}} and {{{ g(x) = 6x }}} then (f ○ g)(x) = (g ○ f) {{{ (x) }}}
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Functions
-> SOLUTION: What makes this statement false?
if {{{ f(x) = x + 1 }}} and {{{ g(x) = 6x }}} then (f ○ g)(x) = (g ○ f) {{{ (x) }}}
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You can put this solution on YOUR website! What makes this statement false?
if f(x) = x + 1 and g(x) = 6x then (fog)(x) = (gof)(x)
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fog(x) = f[g(x)] = f(6x) = 6x+1
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gof(x) = g[f(x)] = g(x+1) = 6(x+1) = 6x+6
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Ans: 6x+1 is not equal to 6x+6
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Cheers,
Stan H.
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