SOLUTION: What is the inverse equation for: h(x)= (2x-1)/(x+1)

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Question 1046875: What is the inverse equation for:
h(x)= (2x-1)/(x+1)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the inverse equation for:
h(x)= (2x-1)/(x+1)
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1st: Interchange x and y to get:
x = (2y-1)/(y+1)
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2nd: Solve for "y"::
xy+x = 2y-1
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xy-2y = -(x+1)
y(x-2) = -(x+1)
y = -(x+1)/(x-2)
That is the inverse.
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Cheers,
Stan H.
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