SOLUTION: Let \[f(x) =
\begin{cases}
9x+4 &\text{if }x\text{ is an integer}, \\
\lfloor{x}\rfloor+5 &\text{if }x\text{ is not an integer}.
\end{cases}
\]Find $f(\sqrt{29})$.
Algebra ->
Functions
-> SOLUTION: Let \[f(x) =
\begin{cases}
9x+4 &\text{if }x\text{ is an integer}, \\
\lfloor{x}\rfloor+5 &\text{if }x\text{ is not an integer}.
\end{cases}
\]Find $f(\sqrt{29})$.
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Question 1045877: Let \[f(x) =
\begin{cases}
9x+4 &\text{if }x\text{ is an integer}, \\
\lfloor{x}\rfloor+5 &\text{if }x\text{ is not an integer}.
\end{cases}
\]Find $f(\sqrt{29})$. Answer by solver91311(24713) (Show Source):
5 squared is 25 and 6 squared is 36, so the square root of 29 must be between 5 and 6. Hence, the Greatest Integer function of the square root of 29 must be 5.
John
My calculator said it, I believe it, that settles it
