SOLUTION: When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0? a.)h(5) b

Algebra ->  Functions -> SOLUTION: When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0? a.)h(5) b      Log On


   



Question 1045147: When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0?
a.)h(5)
b.) h(6)
c.) h(8)
d.) h)9)

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
You make better sense of this when put h into standard form.

y=a%28x-h%29%5E2%2Bk, standard form.

y=a%28x-4%29%5E2%2B7 and you have a point, (2,0).
Think of how a parabola is symmetric.
Can you judge that a%3C0 ?

a%28x-h%29%5E2%2B7=y
a%28x-h%29%5E2=y-7
a=%28y-7%29%2F%28x-h%29%5E2
a=%280-7%29%2F%282-4%29%5E2
a=-49%2F2

y=-%2849%2F2%29%28x-4%29%5E2%2B7
Find BOTH zeros!

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

When the function y=h(x)=ax^2+bx+c is graphed in the x-y plane, the result is a parabola with vertex at (4,7). If h(2)=0, which of the following must also equal to 0?
a.)h(5)
b.) h(6)
c.) h(8)
d.) h)9)
y+=+h%28x%29+=+ax%5E2+%2B+bx+%2B+2
y+=+a%28x+-+h%29%5E2+%2B+k ------- Vertex form
0+=+a%282+-+4%29%5E2+%2B+7 ------ Substituting 0 for y, 2 for x, 4 for h, and 7 for k
0+=+4a+%2B+7
- 7 = 4a_______%28-+7%29%2F4 = a
Function: matrix%281%2C3%2C+y%2C+or%2C+h%28x%29+=+%28-+7%2F4%29%28x+-+4%29%5E2+%2B+7%29
Now, you can substitute each answer choice into the above function to see which one gives a value of 0, or you can easily look at the equation
and determine WHAT VALUE x can be replaced with, and when combined with - 4, and the result is squared, results in a value of 4. That MUST be 6.
Therefore, it must be highlight_green%28matrix%281%2C4%2C+h%286%29%2C+or%2C+CHOICE%2C+b%29%29