SOLUTION: Let f(x)=x^3+7x^2 and g(x)=10x^2-11. f/g is undefined when x=

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Question 1035115: Let f(x)=x^3+7x^2 and g(x)=10x^2-11.
f/g is undefined when
x=
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Division by zero, i.e., zero denominators, cause
an expression to be undefined.

f%2Fg=%28x%5E3%2B7x%5E2%29%2F%2810x%5E2-11%29

That has a denominator 10x²-11, and the expression for f/g
will be undefined when the denominator 10x²-11 equals 0.

So solve 10x²-11 = 0 for the two values of x which cause
the denominator to be equal to zero, (making f/g undefined).

To do that:

Add 11 to both sides.  Divide both sides by 10 to get only
x² on the left.  Then use the square root principle with 
the ±.  That will give you two values when the denominator
equals 0 making f/g undefined.

Edwin