SOLUTION: f(x)= (2x^2-7)/x+2, prove with appropriate limit and work that a slant asymptote exists.

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Question 1029969: f(x)= (2x^2-7)/x+2, prove with appropriate limit and work that a slant asymptote exists.
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29=+%282x%5E2-7%29%2F%28x%2B2%5E%22%22%29

        2x-4
x+2)2x²+0x-7
    2x²+4x
       -4x-7
       -4x-8
           1

So f%28x%29+=+2x-4%2B1%2F%28x%2B2%29

Our claim is that the slant asymptote is 

g(x)=2x-4.

So we prove that the difference between 
f(x) and g(x)
as x approaches ħinfinity is 0.

%22%22=%22%22

%22%22=%22%22




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Edwin