Question 1026024: What is the domain and range of
y=x+1
y+x^2+1
y=√x+1
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! y=x+1; domain and range are both (-oo,+oo)
y=x^2+1; domain is infinite (-oo,+oo); range is [1,oo), because x^2 is never less than 0.
y=sqrt(x)+1. If that is how it should be written, the domain of x is [0,oo); the range is [1,oo)
if sqrt(x+1), then domain is [-1,oo), range [0,oo)
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