SOLUTION: f(x)=x^4-ax^2
When a = 2, there is more than one critical point.
Considering the x-coordinates of the critical points, what is the value of the greatest x-coordinate, giving
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-> SOLUTION: f(x)=x^4-ax^2
When a = 2, there is more than one critical point.
Considering the x-coordinates of the critical points, what is the value of the greatest x-coordinate, giving
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Question 1021851: f(x)=x^4-ax^2
When a = 2, there is more than one critical point.
Considering the x-coordinates of the critical points, what is the value of the greatest x-coordinate, giving your answer to 2 decimal places? Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! The critical points on the graph of the function are those where you can find local extrema (derivative either 0 or does not exist). Since the function is a polynomial, the derivative exists everywhere, and you only have to set the derivative equal to 0 to find the critical points.
For f(x) = , y' = .
Setting y' to 0, we get x = -1,0,1.
You can now finish the solution.