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Question 100547: 1) find F(0) when f(x)=x^2-5x-7
2) Find F(17) when f(x)=|x-16|
all help is appreciated
Answer by bucky(2189)   (Show Source):
You can put this solution on YOUR website! find f(0) when f(x)=x^2-5x-7
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This problem just tells you to take the given function of x, to substitute zero for x in
that function, and then evaluate the function.
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So, start with:
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f(x) = x^2 - 5x - 7
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substitute zero for x and you get:
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f(0) = 0^2 - 5*0 - 7
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The two terms that contain zero on the right side disappear because they each involve a
multiplication by zero, and you are left with the answer of:
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f(0) = -7
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Next problem:
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Find f(17) when f(x)=|x-16|
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Start with the function:
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f(x) = |x - 16|
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then substitute + 17 for every x you see to get:
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f(17) = |17 - 16|
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combine the two terms inside the absolute value signs to get:
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f(17) = |+1|
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and the absolute value of a quantity is the positive value of the quantity. So the answer
is:
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f(17) = +1
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Hope this helps you to understand how to evaluate functions and how to interpret what the
notation means.
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