SOLUTION: The parabola y=ax^2+k has vertex (0,7) and passes through the point (3,2). Find its equation.

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Question 1002163: The parabola y=ax^2+k has vertex (0,7) and passes through the point (3,2). Find its equation.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The parabola y=ax%5E2%2Bk has vertex (0,7) and passes through the point (3,2).
Find its equation.
use vertex form of parabola:
y=a%28x-h%29%5E2%2Bk....if vertex (0,7), we have
y=a%28x-0%29%5E2%2B7
y=ax%5E2%2B7......use point (3,2) to find a
2=a%2A3%5E2%2B7
2=9a%2B7
2-7=9a
-5=9a
a=-5%2F9
so, your equation is: y=-%285%2F9%29x%5E2%2B7