SOLUTION: Wrote it wrong the first time. Find the horizontal asymptote f(x) = (8x)/(1+4x^2) I got 0 for a single asymptote. However, my program tells me this is wrong. Thank you

Algebra ->  Functions -> SOLUTION: Wrote it wrong the first time. Find the horizontal asymptote f(x) = (8x)/(1+4x^2) I got 0 for a single asymptote. However, my program tells me this is wrong. Thank you      Log On


   

Question 1000867: Wrote it wrong the first time.
Find the horizontal asymptote
f(x) = (8x)/(1+4x^2)
I got 0 for a single asymptote. However, my program tells me this is wrong.

Thank you
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Degree of denominator is greater than degree of numerator, so as x goes unbounded either to the more negative, or to the more positive, the SIZE of f(x) becomes increasingly small, in this case, nearer to zero.

.... You could see a 2%2Fx or -2%2Fx happening that way; and you should understand for extreme of x, this gets very near but never reaches 0.

highlight%28y=0%29, the horizontal asymptote.