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Question 1000357: Plz help me to explaain the range of this quadratic equation.{f(x)=1÷sqrt(x^2-2x-3)}
Answer by josgarithmetic(39618)   (Show Source):
You can put this solution on YOUR website! That is a rational function, and not a quadratic equation.
Make the two critical values for x, -1, and +3.
x must not be between those values but can be at either of them.
The denominator of the function will never be negative, so f will never be negative.
can be very near to 0, but it must never become 0 in the function because  is in the denominator. Now, according to this requirement,  OR  .
As x approaches either critical x value, f tends toward positive infinity, no bound. As x goes infinitely to the left or infinitely to the right, f approaches but never reaches 0.
The RANGE for f(x) is  .
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