SOLUTION: What is the function F(x)= 4x^2+16x+8 vertex?

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Question 994288: What is the function F(x)= 4x^2+16x+8 vertex?
Answer by ikleyn(52754) About Me  (Show Source):
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What is the function F(x)= 4x^2+16x+8 vertex?
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For the quadratic function  y = ax%5E2%2Bbx%2Bc  x-coordinate of the vertex is  x%5B0%5D = -b%2F2a.

In this case it is  x%5B0%5D = -16%2F%282%2A4%29 = -2.

To determine the  y-coordinate of the vertex,  substitute this value of  x%5B0%5D = -2  into the quadratic function.  You will get

y%5B0%5D = 4%2A%28-2%29%5E2+%2B+16%2A%28-2%29+%2B+8 = 4*4 - 32 + 8 = -8.

So,  the vertex is  (x,y) = (-2, -8).




Plot of 4x%5E2+%2B+16x+%2B+8