SOLUTION: find the equation for a linear function g(x) which is perpendicular to the line 3x-4y=16 and intersects the line 3x-4y=16 at x=20.

Algebra ->  Functions -> SOLUTION: find the equation for a linear function g(x) which is perpendicular to the line 3x-4y=16 and intersects the line 3x-4y=16 at x=20.      Log On


   

Question 993786: find the equation for a linear function g(x) which is perpendicular to the line 3x-4y=16 and intersects the line 3x-4y=16 at x=20.
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
3x-4y=16
Slope perpendicular, -4%2F3.

-4y=16-3x
y=-4%2B%283x%2F4%29
y=-4%2B%283%2A20%2F4%29
y=-4%2B15
y=11
Point is (20,11).

g%28x%29-11=-%284%2F3%29%28x-20%29, point-slope form
g%28x%29=-%284%2F3%29x%2B4%2A20%2F3%2B11
g%28x%29=-%284%2F3%29x%2B80%2F3%2B33%2F3
highlight%28g%28x%29=-%284%2F3%29x%2B113%2F3%29, slope intercept form, here same as functional form.