SOLUTION: come up with a polynomial function that goes through these four points: (0, 0) (1, 2) (3, -2) (5, 5) Thank you.

Algebra ->  Functions -> SOLUTION: come up with a polynomial function that goes through these four points: (0, 0) (1, 2) (3, -2) (5, 5) Thank you.      Log On


   



Question 975778: come up with a polynomial function that goes through these four points:
(0, 0)
(1, 2)
(3, -2)
(5, 5)
Thank you.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
We have 4 points, and a cubic (3rd degree) polynomial has 4 
coefficients, so we will assume a cubic polynomial function:

y%22%22=%22%22Ax%5E3%2BBx%5E2%2BCx%2BD

We substitute each point:

0%22%22=%22%22A%2A0%5E3%2BB%2A0%5E2%2BC%2A0%2BD
2%22%22=%22%22A%2A1%5E3%2BB%2A1%5E2%2BC%2A1%2BD
-2%22%22=%22%22A%2A3%5E3%2BB%2A3%5E2%2BC%2A3%2BD
5%22%22=%22%22A%2A5%5E3%2BB%2A5%5E2%2BC%2A5%2BD

That simplifies to this system of equations:

system%28D=0%2CA%2BB%2BC%2BD=2%2C27A%2B9B%2B3C%2BD=-2%2C125A%2B25B%2B5C%2BD=5%29

Since D=0 the system reduces to

system%28A%2BB%2BC=2%2C27A%2B9B%2B3C=-2%2C125A%2B25B%2B5C=5%29

We can divide the last equation by 5, so it simplifies further to:

system%28A%2BB%2BC=2%2C27A%2B9B%2B3C=-2%2C25A%2B5B%2BC=1%29

Solve that system and get A=13%2F24, B=-7%2F2, C=119%2F24,
and we already had D=0.

So

y%22%22=%22%22Ax%5E3%2BBx%5E2%2BCx%2BD

becomes f%28x%29%22%22=%22%22expr%2813%2F24%29x%5E3-expr%287%2F2%29x%5E2%2Bexpr%28119%2F24%29x

Edwin