SOLUTION: If a sequence is defined recursively by k(0)=2 and k(x+1) = 3k(x)-5 for x is greater than or equal to 0, then k(3) is equal to what value?
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Question 967148: If a sequence is defined recursively by k(0)=2 and k(x+1) = 3k(x)-5 for x is greater than or equal to 0, then k(3) is equal to what value? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If a sequence is defined recursively by k(0)=2 and k(x+1) = 3k(x)-5 for x is greater than or equal to 0, then k(3) is equal to what value?
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k(0)= 2
k(x+1) = 3k(x)-5
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k(1) = 3*2-5 = 1
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k(2) = 3*1-5 = -2
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k(3) = 3*(-2)-5 = -11
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Cheers,
Stan H.
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