SOLUTION: Is it possible for x=-2 to be in the Domains of the functions: a.) R(x)= 3x^3 - 5x + 6 (all over) x + 2 b.) {{{ H(x)= sqrt( x+1 ) }}} Explain why or why not

Algebra ->  Functions -> SOLUTION: Is it possible for x=-2 to be in the Domains of the functions: a.) R(x)= 3x^3 - 5x + 6 (all over) x + 2 b.) {{{ H(x)= sqrt( x+1 ) }}} Explain why or why not       Log On


   

Question 949267: Is it possible for x=-2 to be in the Domains of the functions:
a.) R(x)= 3x^3 - 5x + 6 (all over) x + 2
b.) +H%28x%29=+sqrt%28+x%2B1+%29+
Explain why or why not for each function. What are the Domains of the functions R(x) and H(x)? If required, use inf for the infinity sign.
Thank You for any help you can provide, I cannot find how to figure out these questions in my notes anywhere so if you can explain how you received each answer that would be great. Thank you again!

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
divided by x+2 means that it is equal to 0 if x = -2 which means it can't be in the domain because then the value of R(x) is undefined because of a division by 0.

when x = -2, sqrt(x+1) is equal to -1 so x = -2 can't be in the domain because the answer would not be real. You would get sqrt(-1) which is imaginary.