SOLUTION: The plug is pulled from a small hot tub. The table gives the volume of water in the tub (in liters) from the time (in seconds) it is pulled until it is empty. Draini

Algebra ->  Functions -> SOLUTION: The plug is pulled from a small hot tub. The table gives the volume of water in the tub (in liters) from the time (in seconds) it is pulled until it is empty. Draini      Log On


   

Question 927534: The plug is pulled from a small hot tub. The table gives the volume of water in the tub (in liters) from the time (in seconds) it is pulled until it is empty.

Draining Water from a Hot Tub
Time(s) Volume(L)
0 1600
10 1344
20 1111
30 900
40 711
50 544
60 400
70 278
80 178
90 100
100 44
110 11
120 0
Determine the average rate of change from s=20 to s=60
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The plug is pulled from a small hot tub. The table gives the volume of water in the tub (in liters) from the time (in seconds) it is pulled until it is empty.

Draining Water from a Hot Tub
Time(s) Volume(L)
0 1600
10 1344
20 1111
30 900
40 711
50 544
60 400
70 278
80 178
90 100
100 44
110 11
120 0
Determine the average rate of change from s=20 to s=60
----------
You don't need all those numbers to do that.
---
The plug is pulled from a small hot tub. The table gives the volume of water in the tub (in liters) from the time (in seconds) it is pulled until it is empty.

Draining Water from a Hot Tub
Time(s) Volume(L)
20 1111
60 400
---
Determine the average rate of change from s=20 to s=60
Avg L/sec = (1111 - 400)/(60-20)
= 711/40
= 17.775 liters/sec
-----------
You might make it -17.775 since it's decreasing.