SOLUTION: State the domain of the following Question 1 a) f(x)=suareroot x+4 b) g(x)= 2x+1/x-3 c) h(x)= 3x^2+5x-3 d) l(x)= 2x+3 m(x)= 3/x^2+7

Algebra ->  Functions -> SOLUTION: State the domain of the following Question 1 a) f(x)=suareroot x+4 b) g(x)= 2x+1/x-3 c) h(x)= 3x^2+5x-3 d) l(x)= 2x+3 m(x)= 3/x^2+7      Log On


   

Question 92246: State the domain of the following
Question 1

a) f(x)=suareroot x+4
b) g(x)= 2x+1/x-3
c) h(x)= 3x^2+5x-3
d) l(x)= 2x+3
m(x)= 3/x^2+7
Found 2 solutions by stanbon, Nate:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
State the domain of the following
Question 1
a) f(x)=suareroot(x+4)
All Real numbers >=-4
------------------------
b) g(x)= 2x+1/x-3
All Real numbers except x=3
-----------------------
c) h(x)= 3x^2+5x-3
All real numbers
---------------------
d) l(x)= 2x+3
All Real numbers
----------------------------
m(x)= 3/x^2+7
All real numbers
=========================================
Cheers,
Stan H.

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
a) f(x) = squareroot (x + 4)
You can not take the square root of a number less than zero....
x+%2B+4+%3E=+0
x+%3E=+-4
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Csqrt%28x+%2B+4%29%29
b) g(x)= (2x + 1)/(x - 3)
The denominator can not be zero....
x+-+3+=+0
x+=+3
Domain: All Reals Save for 3
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C%282x+%2B+1%29%2F%28x+-+3%29%29
c) h(x)= 3x^2 + 5x - 3
There are no limits by the domain of a parabola ... Domain: All Reals
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C3x%5E2+%2B+5x+-+3%29
d) l(x)= 2x + 3
There are no limits by the domain of a linear line ... Domain: All Reals
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C2x+%2B+3%29
m(x)= 3/(x^2 + 7)
The denominator can not be zero.... x^2 will never be negative ... Domain: All Reals
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C3%2F%28x%5E2+%2B+7%29%29