SOLUTION: With the problem: {{{ 2(x-5)(2x+3)+2(x-5)^2 = 0 }}} Why do we factor out the 2(x-5)? what rule is this I don't recall this method. Thanks

Algebra ->  Functions -> SOLUTION: With the problem: {{{ 2(x-5)(2x+3)+2(x-5)^2 = 0 }}} Why do we factor out the 2(x-5)? what rule is this I don't recall this method. Thanks      Log On


   

Question 907332: With the problem: ++2%28x-5%29%282x%2B3%29%2B2%28x-5%29%5E2+=+0++ Why do we factor out the 2(x-5)? what rule is this I don't recall this method.
Thanks
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
It's the distributive property that allows you to factor it out.
++2%28x-5%29%282x%2B3%29%2B2%28x-5%29%5E2+=+0++
++2%28x-5%29%282x%2B3%2Bx-5%29+=+0++
++%28x-5%29%283x-2%29+=+0++