SOLUTION: Please help solve. I was able to put g(x) = 5x^2 − 30x + 55 into standard form like so g(x) = 5(x − 3)^2 + 10 I understand that the vertex is (3,10) however what does t

Algebra ->  Functions -> SOLUTION: Please help solve. I was able to put g(x) = 5x^2 − 30x + 55 into standard form like so g(x) = 5(x − 3)^2 + 10 I understand that the vertex is (3,10) however what does t      Log On


   

Question 905138: Please help solve. I was able to put g(x) = 5x^2 − 30x + 55 into standard form like so g(x) = 5(x − 3)^2 + 10 I understand that the vertex is (3,10) however what does the g mean in this? I know it's a variable but I have a problem asking me if it's greater than or less than zero. I don't know how to find this. Also asking for it's max and min value which I think is the vertex and if it's upward then it's only a min because it's showing it's lowest point and the rest exceeds infinitely. Does that all sound correct?
Here is the problem I am confused about:
http://i.imgur.com/EVIiBCc.png
Thank you
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
g is just the name of the function of x%7D%7D.+%0D%0AWhen+you+graph+the+function+you+usually+use+%7B%7B%7By as the variable.
y=5%28x-3%29%5E2%2B10
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graph%28300%2C300%2C-7%2C7%2C-2%2C12%2C5%28x-3%29%5E2%2B10%29
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OK, so what does vertex form tell you.
The vertex is at (3,10).
Since 5%3E0, the parabola opens upwards at the value at the vertex is the minimum value of the function.
So g%28x%29%3E=10 for all x.
Since 10%3E0 then g%28x%29%3E0 for all x.
Yes, min value is g%283%29=10 and there is no max value.