SOLUTION: calculate the indicated value. f(x) = 14x^2 + 15x - 14 g(x) = 14x^2 + 11x - 10 find f(f(4)) I plugged in 4 for x and came to f(4)=270, would that mean that f(f(4))=270, an

Algebra ->  Functions -> SOLUTION: calculate the indicated value. f(x) = 14x^2 + 15x - 14 g(x) = 14x^2 + 11x - 10 find f(f(4)) I plugged in 4 for x and came to f(4)=270, would that mean that f(f(4))=270, an      Log On


   



Question 84004: calculate the indicated value.
f(x) = 14x^2 + 15x - 14
g(x) = 14x^2 + 11x - 10
find f(f(4))
I plugged in 4 for x and came to f(4)=270, would that mean that f(f(4))=270, and that I should plug in 270 which I think brings me to an answer of 10210036? Whats confusing me is that g(x) = 14x^2 + 11x - 10 is part of the question but it dosent ask to find g(f(4)) so Im not sure what to do with that part of the question.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 14x^2 + 15x - 14
g(x) = 14x^2 + 11x - 10
find f(f(4))
----------------
f[f(4)] = f[14*4^2+15*14-1]
=f[420]
=14*420^2 + 15*420-14
=2,469,796
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Comment: You are right; the g(x) is not part of f[f(4)].
Cheers,
Stan H.