SOLUTION: Help me solve g(h(15)) if g(x)=70 h(x)= -x^2 + 6x

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Question 72596: Help me solve
g(h(15))
if
g(x)=70
h(x)= -x^2 + 6x

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
g%28x%29=70 and h%28x%29=+-x%5E2+%2B+6x
.
You are then asked to find g(h(15))
.
Once you understand the process, you can do this one by inspection. But let's work it
the "long" way. What this problem tells you to do is to first find h(15). To do that means
to just take the equation for h(x) and substitute 15 for all the x's in the equation.
Doing that results in:
.
h%2815%29+=+-%2815%5E2%29+%2B+6%2A15+=+-225+%2B+90+=+-135
.
Now you know that h(15) = -135 and since you are being asked to find g(h(15)) you can
substitute -135 for h(15). Therefore, you are being asked to find g(-135) which tells you
to go to the equation for g(x) and substitute -135 every where that x appears in the equation.
.
Note now that there are no x terms in the right side of the equation for g(x). So you can
write that:
.
g%28-135%29+=+70
.
because there is nothing on the right side where a substitution can be made. Therefore,
the answer to your problem is:
.
g%28h%28x%29%29+=+g%28-135%29+=+70
.
With a little more practice and experience you could have looked at the expression for
g(x) and recognized that no matter what x was (a number or in this case h(x)) it wouldn't
change the right side of g(x). g(x) would always be 70.
.
Hope this adds a little to your understanding of terms such as g(x), b(x), m(x), and so forth.