SOLUTION: Given f(x)=2x^2+3x+5 and g(x)=3x+4 what is f/g)(2)? I have done the addition, subtraction, and multiplication of this problem but completely forgot how to do division. Any help wil
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-> SOLUTION: Given f(x)=2x^2+3x+5 and g(x)=3x+4 what is f/g)(2)? I have done the addition, subtraction, and multiplication of this problem but completely forgot how to do division. Any help wil
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Question 707071: Given f(x)=2x^2+3x+5 and g(x)=3x+4 what is f/g)(2)? I have done the addition, subtraction, and multiplication of this problem but completely forgot how to do division. Any help will be greatly appreciated. Answer by josgarithmetic(39613) (Show Source):
You can put this solution on YOUR website! Long division of polynomials is exactly the same as for decimalized base ten numbers. The SAME process. You are relying on the meaning of expanded form for ordinary numbers; you rely on general form of decreasing degree of the variable for polynomials.
Your desired quotient: 2x^2+3x+5 divided by 3x+4.
How many 3x is in 2x^2? (2/3)x. That is your first partial quotient. Write (2/3)x above the first term. MULTIPLY (2/3)x by 3x+4; and write this result under the first TWO terms of the dividend, and SUBTRACT. Bring down the next term which is the 5.
Continue the process! Either you obtain a remainder or you don't.
For this, the subtraction gave me a (1/3)x. So how many of 3x is in (1/3)x ? There is 1/9, so write 1/9 over the 3x term of the dividend. Multiply (1/9)(3x+4) and subtract from your bottom row of the division work. A remainder of 41/9 is the result.
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